Thursday, March 29, 2007

#9.6
  • (1-17) all
  • add to your concept card stack
  • with the addition of today's 3 definitions, sector, segment, annulus, you should have at least 90 concept (index) cards
  • bring them in tomorrow!

8 Comments:

At Thursday, March 29, 2007 at 4:08:00 PM EST, Blogger dana said...

can someone please help me on number 15. i cant understand it.

Thank you

 
At Thursday, March 29, 2007 at 7:16:00 PM EST, Blogger Keenan said...

Sorry Dana... I just woke up from a over extended nap.... I'll check # 15 out and post what I think

 
At Thursday, March 29, 2007 at 7:29:00 PM EST, Blogger dana said...

thanks keenan =)

o and is anyone going to the library tomorrow morning? cause i went today but there wasnt anyone.

 
At Thursday, March 29, 2007 at 7:29:00 PM EST, Blogger M.Velasco said...

Wowwies.

A few of these problems were a bit of a doozy for me. XD There are a few problems that I had gotten answers for, but that I'm unsure of.

Number twelve just puzzles me. How were you guys able to find the measurement of angle ABC for number twelve? [I would really, really appreciate a hint, or just a notification of which formulas to use and why. Thank you so much in advance!]

Hmm. Numbers fourteen through seventeen. Would it be strange to say that I had gotten the same answers for all of them...?

Dana, I just want to apologize in advance if I'm wrong, but here's what I had done:

You know there are four circles [I can only assume they're congruent...but you know what they say. When you "assume", you make a you-know-what out of "u" and "me". *dies* XDDD Aaah.] in a square with a base of twelve and a height of twelve.

What I did first was find the area of the square, so you know. Twelve times twelve, bada-bing, bada-boom: 144. [144 cm^2]

The next thing I did was to examine each circle individually and find the area of one circle. The formula of a circle is A= pir^2.

You know that the circles are externally tangent, so they are tangent to each other and to the same line at the same point. If you look at the two circles tangent to a height of the square [look at the two circles vertically arranged to the left-hand side. The side would act as the tangent, and each circle has a point on the side.] I don't know how to explain this without sounding so vague...

Yeah. Ignore that above. I was just rambling. I'll just leave it up there for someone to intelligently elaborate for me. XD

But. Erm. Basically, I thought, "Hey! Each of those circles have to have a diameter a six." Why? [Because I said so!] Because I just. Erm. Kind of thought, hey six and six maaake a twelve riiiight? What's the harm in trying. ...*looks away*

So, yeah! If each circle has a diameter of six, then they each have a radius of three. So now you can find the area of each circle:

A= Pi-r^2.
A= Pi (3)^2.
A= 9pi. [9pi is about 28.26 or 28.27 depending on whether you use 3.14 or the pi key by default.]

So, an individual circle has an area of 28.26. Now just multiply that by four to get the sum of the areas of the four circles. You'd get 113.04. [Or 113.08 depending whether or not you used 28.27]

Now, it's asking you what percentage the areas of circles cover on the area of the square. I just set up a proportion.

144=100. [Because the area of the square is one hundred percent of the area of the square. XD]

My proportions were 144 over 113.04 is equal to 100 over x.

113.04 times 100/144= 78.5

So would the answer be 78.5%...? I'm not so sure. Please don't trust me, Dana. I could be wrong, but if someone could bounce off my mistakes...? That would be helpful. XD

Could someone go over number twelve and thirteen with me? I had gotten an answer for number thirteen, but Nick and I got toe-tay-lay different answers, it made me freak out and doubt my own. XD

Thank you in advance!

Sincerely,
--Mary.

P.S. Keenan, I think this nap thing is contagious. XD [And gyaaah! I still have to do all of Mister Haggard's work. I'm waaaasting away. *flaaails*]

 
At Thursday, March 29, 2007 at 7:39:00 PM EST, Blogger dana said...

thank you sooooooo much mary!
i really appreciate it.

 
At Thursday, March 29, 2007 at 7:48:00 PM EST, Blogger M.Velasco said...

You're very welcome, Dana. ^-^

[I just want you to know now that I'm so, so, so, sosososo sorry if I'm wrong. >.<; I don't want to give you an invalid answer, but that's all I could think to do. If someone has a different result, please share!]

I'll see you at the library tomorrow, by the way. XD Nick just asked me the same thing earlier.

Sincerely,
--Mary.

P.S. On a side note, I'd like to announce something. XD *clears throat.*

Ahem. On Monday, the first time my PE class played a game outside, I, MaryElysee Velasco, painfully got nailed in the face with a soccer ball.

But today, on March 29, 2007 at exactly 12:15 during third period, I have redeemed myself by nearly making a touchdown while we were playing flag football from practically one side of the field to the other.

Yes. That is all. XDDDD ...*rolls awaaaay* AAAAH. I need a life.

 
At Thursday, March 29, 2007 at 7:57:00 PM EST, Blogger dana said...

lol. well congratulations on ur nearly touchdown.

its ok if your wrong, as long as you tried helping a me, i really appreciate it. thank you again =) plus it was much better than the answer i had.

well i guess ill see u tomorrow at the library.

o and nick you better not come 5 minutes before the bell rings like u do all the time lol.

 
At Thursday, March 29, 2007 at 9:54:00 PM EST, Blogger Keenan said...

Mary thats the same thing I got... YAY

But ummm I dont get #12... BOOOO

Good job on the touchdown.... I gotta teach my famous touchdown dance!

 

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