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#9.3
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posted by msichan @ 10:24 AM
Tuesday, March 27, 2007
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11 Comments:
Hello everyone.. Umm I just need to verify some of these answers..... # 6 On 9.2 I got (4.8) seemed to easy to me I dont think I got it right..
Also can someone explain # 7 on 9.2 I am kind of stuck..
Thanks... Keenan
[Woaaah. I just got this mega-weird phone call. This telemarketer lady was all like, "E'llo, doo youah spic'eh Spanish?" So I said, "No, I'm sorry--" and then she hung up. XDDD AAAH. HAAA. That entertained me for about two seconds of my life.]
Anyway! On topic.
Hey, Keenan. ^-^
Hmm. For number six in section 9.2, I'd have to say I agree with you. And if you don't think you got it right, then I probably got it wrong, too.
Did you first do eight multiplied by six to find the area of the "whole parallelogram" if there was a parallelogram to get forty-eight before you divided it by half to get twenty-four, the would-be area of the triangle? And then the whole 24= 1/2(10)h thing? That's what I had done, as well.
Number Seven: Section 9.2:
Apologies in advance, Keenan, if I'm wrong.
You know they're asking you to find the perimeter. You know you need to find the measurement of the base, the remaining side of the triangle, in order to find the perimeter.
Since they already gave you the area and the height, you can find the base.
A= (1/2)bh.
924= (1/2)b(24).
1848= b(24)
1848/24=b(24)/24.
b= 77.
So, the base is 77 centimeters. Just add all the sides of the triangle to get the perimeter. ^-^
Sincerely,
--Mary.
P.S. I would really appreciate a hint for number eight on section 9.2, please. ^-^ Thank you in advance. [Ooh, please don't give me the answer! Just a hint will be fine.]
hey keenan, ya i got 4.8 too.
and for number 7 you have to set up the equation for the triangle, it would be 924 = 1/2(b)(24).
Then when you find the base, you add find the sum of base + 51+ 40. and that would be the answer.
GOD BLESS YOU MARY & DANA!!!!
Hopefully I didnt affend your religions. Anyway I just thouht these answers were way to easy thats why I posted it.
UMM.. # 8 Is too HARD for me to figure out sorry. I'll asks Nick
Anyone up for a quick study group in the morning to go over 1-6 in the second lesson???
ya i might go.
im most likely going but im not sure
hey peoples iz stefan
UMmMmMmMmM i dont get # 23 on 9.2
can somebody PLEASE help me
tanks a bunch
Ooh! Keenan, Dana. If you guys are going to be there tomorrow, then gyaaah. So will I. XD I'm working on number five on section 9.3 right now. Fwee~. So, I'll see you both tomorrow.
Hey, Stefan.
I honestly don't know what to tell you, since I was a bit confused too. *headscratch* Well, it says that P is an arbitrary point. And arbitrary means undetermined, I think. ...So I suppose this means it's all visual judgment? Ahahaha. I think it's the same for number twenty-four.
Speaking of number twenty-four! Gyaah. Can someone help me explain why I think it's less than half? XD Because like, for seriously, I'm about to write:
"Er. Well, y'see that iddy-bitty widdle corner of the bottom card peeking out there...? Since that's uncovered and um...the top card is sort of like...slanted ...like
...diagonally over the uh..bottom card. So you can see...more than half of the bottom card?"
Yes. I'm clueless. Someone think of something intelligent to say, please. XD Or explain which answer is correct. I'd be eternally grateful.
...Hmm. And number twenty-six and twenty-eight were a bit of an iffy for me, too. And has someone got number eight yet? [Aaaaah. XD So many questions. *falls on knees and bows!* I'm so sorry. XD Please help me. Bwaaah.]
Thank you in advance!
Sincerely,
--Mary.
mary for #24 i actually made a visual with actual cards and it dawned on me that:
Since cards are rectangle
their diagonals divide it into 2 congruent triangles.
in the pic u see it covers more than the diag
So it actually covers more than half of the bottom card
Well, that was a smart idea. I think that I was too afraid to compare them to rectangles since the edges of the cards were rounded. XD Though, problem is subjected on caprice and personal discretion, so the way you presented your information really does make sense. I trust in your judgment, then. Thank you, Stefan! *peace-sign!*
Hmm. Hey, if anyone is still awake, would you mind taking a quick look at number six in section 9.3 for me? For some reason, the image in my book looks a bit faded. Are the exterior walls...? Erm. Gyaah. Yeah. I just can't see it. Is the length on the furtherest right near 18m 28? XDDD Aaah. Sorry, sorry again.
Sincerely,
--Mary.
P.S. Just for a reassurance here, the "exterior walls" of the cabin doesn't include the roof, does it...? XD Or would it because it's a "vertical surface"?
i will be there too. library??
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