- (1-9, 12) all
- (13-19) all
#4.3
- (1-30) all
- (35-37) all
#4.4
- I.4.4.3 or I.4.4.4
- just as long as you know what the special relationship between the slopes of perpendicular lines is
you MUST post an answer tonight.
make sure you label your answer. for example,
#4.3, #8 is ....
posted by msichan @ 9:07 AM
35 Comments:
Hey guys, this is chen and just checking in with the class.
Chen
The answer to number one is: If lines r and s are parallel and are cut by a transversal then w=63, because it is an (AIA) to the given measurement.
This is a direct reference to Copnjecture C-17b.
Better yet it should say, "to the given angle measurement", instead. My bad.
This is also, for Section 4.2 #1
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4.2 #3
Yes, line k is parallel to line l. Both lines do no intersect and are coplaner.
02/13/07--
Hmm. Actually, Dana, I'm not sure that's true. The two lines and the transversal aren't even drawn on the plane. And like Ms. Chan said, just because they look parallel, it doesn't make them parallel. Lines extend forever, so if one was even a degree off, they would intersect eventually.
I put that line k is not parallel ti line l because if two parallel lines are cut by a transversal, two consecutive exterior angles are supposed to be supplementary.
68 plus 122 equals 190, not 180.
Sincerely,
--Mary.
Ack! Sorry--I had a few typos.
The two lines and the transversal aren't even drawn on the plane.
I put that line k is not parallel ti line l--
I meant not drawn on a plane. XD And I cannot believed I misspelled "to". ...Wait. Did I even spell "misspell" right? *headscratch*
Sincerely,
--Mary.
ya i get what your saying mary. thanks that helped alot.
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Can Ant one please explain why number 6 on page on 4.2 is 115. I thought AIA (Alternate Inrerior Angles) are congruent?
Any one********
i dont get #9 on 4.2
Hee. You're welcome,Dana. ^-^
Okie dokies. So British answered number one and Dana answered number three; I'm just going to skip to number seven really quick since it follows what I had stated from my last post:
Number Seven--
What's wrong with this picture?
What's wrong is that although the lines are marked as parallel, they are not parallel. This is evident because if the lines were parallel and cut by the transversal, exterior angles are suppose to be supplementary.
The exterior angles here 56-degrees and 114-degrees equal 170 rather than 180, thus proving the lines are not parallel.
Ooh, Keenan!
For number six? The answer is 113. I checked in the back of the book. I'm sorry if I'm incorrect, but here is my personal reasoning. The image shows that there are congruent angles.
Alternate interior angles are congruent; so I marked off where the alternate interior angles were. If you can do that, you'll see z and another 67-degree angle can be a linear pair of angles. So, they'd have to be supplementary.
180 - 67 = 113.
z = 113-degrees.
I'm sorry I can't help you with number nine. I'm only on eight myself. XD
Sincerely,
--Mary.
Aaand, my mistake. For number seven section 4.2, I should have been more specific and said consecutive exterior angles. I'm finishing up number nine, but I'd really appreciate some assistance for number eight. ^-^
Please don't give me the answer. If you solved it, I'll think you're mega-wicked-awesome if you could give me a clue or a hint to help me comprehend the question better so I can determine an answer on my own. XD
Many thanks in advance!
Sincerely,
--Mary.
P.S. And dude. XD Has anyone seen that "The End of The World" flash video? Bwahaahaaa!
For 4.2 #18 you can have multiply answers for y. some I got were 2, 4, 6, and 8. So I think, y is a multiply of 2. (correct me if i am wrong!!)
THANK YOU MARY.... One more question for 4.3 I dont understand number 5-8. I know thats a lot but I am really getting fustrated with all the work that I having a hard time understanding...... In sayin that I would like to state ho much I LOVE Ms. Chan.... Your the best
4.2#5 Quadrilateral FISH is a parallelogram because angles H and I are congruent, therefore, it iz a parallelogram.
just to make sure im right, what does it mean to solve for y?
o and keenan, i myself dont really understand 5-8, i wouldve loved to help you with them but i dont want to give you the wrong answers, sorry.
Ack. Okie dokies, I just finished number five on section 4.3. [Yeah. XD I'm really slow, but can you blame me? I was distracted listening to my Daddy cursing while struggling to assemble a yo-yo for my little brother. A yo-yo. *shakes head* XD! Why buy a yo-yo kit, when you can buy a yo-yo that's already been put together?!]
I'm sorry for the late reply, but here's my answer.
Number Five: Section 4.3
Okie dokies. It's asking you to find the coordinates of the other endpoint. They give you the endpoint [12, -8] of a segment to the midpoint [3, 18]. So visually:
Point A--(12,-8)
Point B--(3,18)
.A------.B------[?]
You're trying to determine the question mark. The other endpoint.
The formula to locate a midpoint as you know is:
(x1+x2/2, y1+y2/2)
Do find the other endpoint, plug in the information you already have!
Remember, the given endpoint is (12, -8) and the midpoint is (3, 18).
So. Let's start by finding the "x" of the other endpoint.
12+x/2=3
12 is x1, "x" is x2. They would equal three, because the "x" of the midpoint is 3. ^-^
After you set that up, just multiply it both sides by two to get:
12+x=6.
Subtract 12 from both sides:
12-12+x=6-12
To get:
x=-6
Now you know the "x" for the other midpoint. Hee. Just follow the same format for "y". To get you started, just solve this:
-8+y/2=18.
It worked for me, but please tell me if I had made any mistake in my calculations. This is my weakest subject, so I would greatly appreciate it.
I'm working on the rest for now. ^-^ But, would someone please be willing to explain number eight for me in section 4.2? Just a hint please. And, for number nine in section 4.2, I'm missing angles i, j, k, and s. Would someone kindly go over them with me? I can help you find other angles if you're missing any.
Thank you in advance!
Sincerely,
--Mary.
__ __
For 4.3 #1 AB=1,CD=undefined,
__ __
EF=2/3, GH=undefined; correct me if wrong please.
Mary, to find angles i, j, k, and s, you need to look at the parallel symbols on each of the lines. L3 and L4 are said to be II, but line L2 is said to be II to L3... then they tell you that L2 is parallel to L1. So lines 1, 2, 3, and 4 must all be parallel to one another. If you know this, then you can use your corresponding/ AIAs and all that good stuff to figure out the measures of those angles. Hint: the 108 degree angle above angle F must correspond to angle k and angle i if those lines are parallel. Which they are. I think.
I think that I'm on track here, but I could be wrong. Sorry if I am!
#4.2 #2: If pIIq and they are cut by a transversal, then x= 90 degrees because its corresponding angle is equal to 90 degrees.
That question was easy. :)
mary, for #8 im just as lost as you. i dont understand it at all.
but for #9 i got
i- 108
j- 108
k- 108
s- 62
now im not 100% sure but thats what i came up with.
-
Dana
I found another way to do #5 on 4.3.
First I put 3=12+x, because to get the missing x(2), I set the already given x plus my new variable x(2) equal to 3. I then subtracted 12 to both sides and got the same answer as if i were to do Mary's way.
I applied the same knowledge as in my previous explanation to the missing y-coordinate and got the same answer as if I would have done it Mary's way. So, there are two ways to find the missing coordinate. This was the first way i tried.
By the way x(2) is not x multiplied by 2. It is actually the variable i used to diffrentiate between the two x's. Try not to get confused. Sorry
Ooh! Keenan, I hope you're still online to see this. I can show you number six on section 4.3 now, as well. ^-^
Number Six: Section 4.3
Once again, before I start explaining, apologies for any mistakes. There's one thing I am uncertain about and it's the diagonals.
It states "Parallelogram ABCD has vertices A (0,0), B (6,0), C (12,8), and D (6,8). Find the midpoints of both diagonals."
First things first, because points A and B have a rise of zero, they are both on the same side. D and C have a rise of eight, so they're on the same side. And the run of each point determine where it is positioned on the parallelogram.
So, here is what I imagined it would look like:
http://tinyurl.com/2xwn2d <--Copy and paste. XD
Now, here comes my "erm. I hope I'm right" moment--the diagonals. Both diagonals. The definition of a diagonal is a line segment that connects two non-consecutive vertices, so I'm assuming the diagonals are AC and BD like so:
http://tinyurl.com/2ejabg <--Copy and paste me again. XD
You'll just have to find the midpoint of A and C, and B and D. ^-^ I hope I was able to help you. I--
GYAAAAH! XDDD *clings to Sara and Dana's ankles* I wuve yoo guys. XB Thank you both so very much for the help; I'm looking over my work now. XD *huuug!*
And wicked, British. XD ...*re-reads*
Sincerely,
--Mary.
The answer to #9: 4.2 is
A=64
B=116
C=116
D=64
E=108
F=72
G=108
H=72
I=108
J=108
K=108
S=72
M=105
N=79
T=119
Q=72
I hope i didnt miss any letters and im prety sure these are right...
aaahhh...i feel so stupid...i just got home from my jazz band evaluation and im sooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo behind in the class...i think im about to rip my hair off...stupid band gets in the way with my school...but whatever i really needed that..i feel a lot better now.. sooo yeah...tomorrow i need all the help i can get on 3.8 in the morning. and also i will need some assisants on the home from yesturday and if i don't finish the hw todasy i might need help on that too. but i will repost if i have any questions on the hw. yes, i don't have an answer to post yet and i don't think i'll have one...i feel soo stupid ok bye
gosh im screwed like a bolt...man. im on number 12 on 4.1!!! im never going to finish but i have to try..
i feel dumb..im lie the only one up still doing hw...oh well i just finished 4.1 but as i look at tonights hw i cry...i hope its not much
andres...you hink YOUR screwed? its 10:27.... i got out of ste practice at 7 my mom was in target so she didnt come and get me until about 8...once i got home i took a sower and started my hw... yeah well i REALLY have 2 push 2 finish...but...
#4.2
#4
i got y=57`
because quadrilateral TUNA is a parallelogram...i think! lol
step practice*
shower**
this is just so crazy..i can't believe how in just one weekend of heck i manage to get from finally caught up in the class with a C all the way to 5 lessons behind and on my way to getting a D again...this is unbelevible. well i guess im going to try and get some of lesson 4.2 down so im not so screwed. ok this is my last post. goodnight. 30 mins till midnight. i better hurry
I FINISHED FINALLY
YEEEYYYY
DIS IS STEFAN OVER-AND-OUT
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